Yeah, I just don't know what the equation would be to calculate that kind of volume, If you did though, you would have to probably end up adding the volume from where it hits the 100m mark for any pieces that fly with an initial velocity helping the fragments move higher from that point after the blast, and then You would have to probably add the Cylinder's volume that gets created from the point where it falls down from the farthest reach at 100m above ground. But for momentum that carries pieces farther than that displacement the last 100m.... I honestly don't know.If I've worked it out correctly, then the X directly to the right of the point of explosion on your diagram is 40.77471948m away, and the X where the fragments would touch the floor is 87.41807227m away from your centre line. I don't know if it helps though, as the path of the projectile is curved so the volume can't be calculated with any simple calculations, it's going to be some hideously complicated differential equation followed by a lovely bit of integration, and the bottom party is the easy bit
I'll ask my differential equations lecturer about this when I go back to uni, there's got to be an equation to use for this :)
I'm assuming that you would need to find the velocity in the horizontal vector for any pieces that keep moving away from the centerpoint of the blast for the last 100m of the fall. Which would be Vmax, and I can get all that, but I don't know anything for volume. I know 2D, not 3D.
Here's my belief though. In theory, i'd assume this is how you would end up getting the result though:
(Image brought to you by Photoshop :thumbsup2:)
I will pass... lol I'm a programmer not a rocket scientist.
These were fun while I didn't require a mathematician to solve them anyways :)